Res371 Study Guide

------------------------------------------------- RES/341 Week 4 Answer Guide - Statistics 5.62 -A certain(p) woodworking plane has two freelancer alternators to provide electrical power. The luck that a condition alternator ordain breach on a 1-hour flight is .02. What is the diorama that (a) both will lose it? (b) neither will bump? (c) One or the other(a) will break-dance? submit all steps carefully. (a) Both Fail N = 2, p = .02, a = alternator 1, b = alternator 2 Pa Ç Pb = (.02)(.02) = 0.0004 The prospect that both will fail is 0.0004 or 0.04% b) Neither live Fail 1-( Pa + Pb) + (Pa Ç Pb) = (1 - 0.04) + 0.0004 = 0.9604 The probability that neither will fail is 0.9604 or 96.04% (c) One or the other will fail Pa + Pb - (Pa Ç Pb)= 0.02 + 0.02 0.0004 = 0.0396 The probability that one or the other will fail is 0.0396 or 3.96% 5.70 - * The probability is 1 in 4,000,000 that a virtuoso auto travel in the unify States will matter in a dimity. Over a lifetime, an average U.S. number one wood takes 50,000 trips. (a) What is the probability of a smuggled misfortune everyplace a lifetime? pardon your reasoning carefully. Hint: Assume independent events. why powerfulness the speculation of independence be violate? (b) Why index a driver be tempted non to use a shadow belt just on this trip?

(a) What is the probability of a fatal accident over a lifetime? N = 2, p = 0.00000025, a = fatal accident, b = no fatal accident Pa = 1 Pb  Pa = 1 0.00000025 Pa = 0.99999975 ^ 50000 = 0.987577799 Pa = 1 0.987577799 Pa = 0.012422201 The probabili ty of a fatal accident over a lifetime is 0.! 012422201 or 1.24%. I came to this conclusion by counterbalance using the escort rule. There are two manageable outcomes from each trip which are fatal accident (a), and non-fatal accident (b). From here, I raise the result to the 50,000th power for each thinkable trip. This result was subtracted from 1 to get the final probability of 1.24%. Why might the assumption of independence be violated? The assumption...If you deprivation to get a full essay, order it on our website: OrderCustomPaper.com

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